Resonance energy will be more if Canonical structure are equivalent than if canonical structure and non- equivalent for the same species .Molecule is aromatic than le is not aromatic .

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Solution

Resonance, as per the definition, is the delocalisation of loosely boned electrons i.e.π electrons (double and triple bond electrons as well).

The answer for the question is just a hypothetical approach to satisfy the stability of the compound!!

“ As the resonance hybrid is the most stable structure among all the structures and each canonical one is unstable structure. The reason behind instability of canonical structure is the dis-balanced chemical bonds or π bonds and dis- continuous charge distribution i.e.+ve and -ve charges or incomplete octet”.

Further more the stability is inversely proportional to the energy.

Hence the resonance hybrid has less energy than canonical structure.

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Similar questions

Q. A canonical structure will be more stable if

Q. Which of the following statements is/are correct regarding the canonical forms given below:

H_{3} P O_{3}

can be represented by structures 1 and 2 shown above. Can these two structures be taken as the canonical forms of the resonance hybrid representing

H_{3} P O_{3}

? If not, give reasons for the same.

$H_{3} P O_{3}$ can be represented by structures 1 and 2 shown below. Can these two structures be taken as the canonical forms of the resonance hybrid representing $H_{3} P O_{3}$ ? If not, give reasons for the same.

S t a t e m e n t - I : - ---------------- -

The canonical forms have no real existence

S t a t e m e n t - I I : - ------------------ -

There is no equilibrium between canonical forms

S t a t e m e n t - I I I : - ------------------- -

The energy of the resonance hybrid is less than the energy of any single canonical structure

S t a t e m e n t - I V : - ------------------ -

The molecule does not exist for a certain fraction of time in one canonical form and for other fraction of time in other canonical form
Correct statements is / are

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