Respected BYJUS faculty

My name is VANDITA YADAV and I am student of BYJUS 9th grade I. C. S. E.

I AM NOT ABLE TO GET THE ANSWER OF THIS QUESTION FROM LOG:

log(x-1)+log(x-1)=log 1 to the base 2.

Thank you.

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Solution

Log 1 base 2 = 0
as 2^0=1.

Now, log(x-1) + log(x+1) =log(1 to the base2)

log(x-1) + log(x+1) = 0

log ( x ^ 2 -1) = 0

10^0 = x ^2 -1

1+1 = x ^2

x = √2

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