Rest mass energy of an electron is :

1.02 MeV

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0.511 KeV

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0.511 MeV

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2.02 MeV

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Solution

The correct option is D 0.511 MeV
According to Einstein's mass-energy equivalence theory, $E_{0} = m_{0} c^{2}$
where $E_{0}$ is the rest mass energy,
$m_{0} = 9.11 \times 10^{- 31} k g$ be the rest mass of the electron and $c$ be the velocity of light.
So, $E_{0} = (9.11 \times 10^{- 31} k g) \times (3 \times 10^{8} m / s)^{2} = 8.19 \times 10^{- 14} J$
$E_{0} = \frac{8.19 \times 10^{- 14}}{1.6 \times 10^{- 19}} e V = 0.511 \times 10^{6} e V = 0.511 M e V$
(note: $1 e V = 1.6 \times 10^{- 19} J$ )

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