The resultant (R) of two forces (A and B) is mathematically represented as
R2 = A2 + B2 + 2ABCosθ
where θ is the angle between forces A and B. Now, as all three forces are equal, so
let R = A = B = x
So,
x2 = x2 + x2 + 2x.xCosθ
or x2 = 2x2 (1 + Cosθ)
1/2 = 1 + Cosθ
thus , Cosθ = -1/2
or θ = 120 o
Regards