Resultant of two vectors A- and B- is inclined at 45o to either of them- What is the magnitude of resultant-

The correct option is C √(A^2+B^2) The resultant makes 45 #176; with A and BTherefore angle between A and B us 90 #176; |A+B|=√(A^2+B^2+2ABcosθ)=√( ...

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Standard XII

Physics

Vectors and Its Types

Resultant of ...

Question

Resultant of two vectors $\to A$ and $\to B$ is inclined at $45^{o}$ to either of them. What is the magnitude of resultant?

A + B

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A - B

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\sqrt{A^{2} + B^{2}}

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\sqrt{A^{2} - B^{2}}

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Solution

The correct option is C $\sqrt{A^{2} + B^{2}}$
The resultant makes 45° with A and B
Therefore angle between A and B us 90°
$| A + B | = \sqrt{A^{2} + B^{2} + 2 A B c o s θ} = \sqrt{A^{2} + B^{2} + 2 A B c o s 90 °} = \sqrt{A^{2} + B^{2}}$

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Resultant of two vectors →A and →B is inclined at 45o to either of them. What is the magnitude of resultant?

The correct option is C √A2+B2The resultant makes 45° with A and BTherefore angle between A and B us 90°|A+B|=√A2+B2+2ABcosθ=√A2+B2+2ABcos90°=√A2+B2

Resultant of two vectors $\to A$ and $\to B$ is inclined at $45^{o}$ to either of them. What is the magnitude of resultant?

The correct option is C $\sqrt{A^{2} + B^{2}}$
The resultant makes 45° with A and B
Therefore angle between A and B us 90°
$| A + B | = \sqrt{A^{2} + B^{2} + 2 A B c o s θ} = \sqrt{A^{2} + B^{2} + 2 A B c o s 90 °} = \sqrt{A^{2} + B^{2}}$