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Question

Resultant of two vectors A and B is of magnitude P. If B is reversed, then resultant is of magnitude Q. What is the value of P2+Q2?

A
2(A2+B2)
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B
2(A2B2)
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C
A2B2
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D
A2+B2
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Solution

The correct option is A 2(A2+B2)
Let θ be angle between A and B
Resultant of A and B is
P=A2+B2+2ABcosθ ...(i)
When B is reversed, then the angle between A and B is (180θ)
Resultant of A and B is
Q=A2+B2+2ABcos(180θ)
Q=A2+B22ABcosθ ...(ii)
Squaring and adding (i) and (ii), we get
P2+Q2=2(A2+B2)

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