Question

Results of calculations for four different designs of a fusion reactor using D-D reaction are given below. Which of these is most promising based on Lawson criterion?

• A. Deuteron density=2.0 x ${10}^{12}{cm}^{-3}$ ,confinement time=5.0 x ${10}^{-3}$s
• B. Deuteron density=8.0 x ${10}^{14}{cm}^{-3}$ ,confinement time=9.0 x ${10}^{-1}$s
• C. Deuteron density=4.0 x ${10}^{23}{cm}^{-3}$ ,confinement time=1.0 x ${10}^{-11}$s
• D. Deuteron density=1.0 x ${10}^{24}{cm}^{-3}$ ,confinement time=4.0 x ${10}^{-12}$s

Answer 1

The correct option is B Deuteron density=8.0 x ${10}^{14}{cm}^{-3}$ ,confinement time=9.0 x ${10}^{-1}$s

According to Lawson, deuteron density (n) and confinement tome $t_0$ must satisfy the criterion

$n{t}_0>5\times {10}^{14}c{m}^{-3}s$

This condition is satisfied only by choice(b) for which $n{t}_0=(8.0\times {10}^{14})\times (9.0\times {10}^{-1})=7.2\times {10}^{14}c{m}^{-3}s$. Hence the correct choice is $\left(b\right)$.