Question

Results of calculations for four different designs of a fusion reactor using D-D reaction are given below.Which of these is most promising based on Lawson criterion?

• A. deuteron density $=2.0\times {10}^{12}c{m}^{-3}$, confinement time $=5.0\times {10}^{-3}s$
• B. deuteron density $=8.0\times {10}^{14}c{m}^{-3}$, confinement time $=9.0\times {10}^{-1}s$
• C. deuteron density $=4.0\times {10}^{23}c{m}^{-3}$, confinement time $=1.0\times {10}^{-11}s$
• D. deuteron density $=1.0\times {10}^{24}c{m}^{-3}$, confinement time $=4.0\times {10}^{-12}s$

Answer 1

The correct option is B deuteron density $=8.0\times {10}^{14}c{m}^{-3}$, confinement time $=9.0\times {10}^{-1}s$

Calculating Lawson number for the 4 cases:

$A:2\times {10}^{12}\times 5\times {10}^{-3}={10}^{10}B:8\times {10}^{14}\times 9\times {10}^{-1}=7.2\times {10}^{14}C:4\times {10}^{23}\times 1\times {10}^{-11}=4\times {10}^{12}D:1\times {10}^{24}\times 4\times {10}^{-12}=4\times {10}^{12}Biscorrectas7.2\times {10}^{14}>5\times {10}^{14}$