The correct option is C 59
Let, x=0.¯¯¯5
⇒x=0.555...⋯(i)
Here, the repeating digit is 5.
Step 1: Place the repeating digit to the left of the decimal point by multiplying it by 10 because the unit digit (0.5) in the tenths place.
⇒10×x=10×0.555...
⇒10x=5.55...⋯(ii)
Step 2: Place the repeating digit to the right of the decimal point.
In equation (i), the repeating digit is already to the right.
Now, from (ii)−(i), we get
10x−x=5.555...−0.555...
⇒9x=5
Dividing both the sides by 9, we get
⇒9x9=59⇒x=59