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Question

Rewrite the quadratic equation 1x+41x7=1130,x4,7
in the standard form of a quadratic equation. Also,identify a,b and c in the given equation.

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Solution

1x+41x7=1130
x7x4(x+4)(x7)=1130
11(x+4)(x7)=1130
(x+4)(x7)=30
x23x28=30
x23x+2=0
On comparing this equation with ax2+bx+c=0, we get
a = 1, b = -3 and c = 2

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