Question

Rewrite the terms in proper order and then divide
$12+10y^3+10y^2+8y-2$ by $y^2-y+6$

Answer 1

The given polynomial $12+10y^3+10y^2+8y-2$ can be rewritten as $10y^3+10y^2+8y+10$.

We now divide $10y^3+10y^2+8y+10$ by $(y^2-y+6)$ as shown in the above image:

From the division, we observe that the quotient is $10y+20$ and the remainder is $-32y-110$.

Hence, the quotient is $10y+20$ and the remainder is $-32y-110$.