Ria booked a cab at 10 pm- Due to peak hours the cab charged 2-5 times the normal fare- If the normal fare is 7293-50 - Find her total fare-A- 7533-25B- -733-75C- - 667-50D- - 867-43

The correct option is B ₹733.75 As the cab charges nbsp;2.5 times the normal fare, the original fare gets multiplied by the extra charges. So, 2.5 × 293.50 ...

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Standard VI

Mathematics

Multiplication of Decimals

Ria booked a ...

Question

Ria booked a cab at 10 pm. Due to peak hours the cab charged 2.5 times the normal fare. If the normal fare is ₹293.50. Find her total fare.

₹667.50

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₹867.43

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₹533.25

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₹733.75

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Solution

The correct option is D
₹733.75

As the cab charges 2.5 times the normal fare, the original fare gets multiplied by the extra charges.

So, $2.5 \times 293.50 = \frac{25}{10} \times \frac{2935}{10} = \frac{73375}{100} = 733.75$ .

Now Ria has to pay ₹733.75 as the total fare.

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Q. If a normal cab fare is ₹293.50, then 2.5 times the fare will be ____________.

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Ria booked a cab at 10 pm. Due to peak hours the cab charged 2.5 times the normal fare. If the normal fare is ₹293.50. Find her total fare.

The correct option is D ₹733.75 As the cab charges 2.5 times the normal fare, the original fare gets multiplied by the extra charges. So, 2.5×293.50=2510×293510=73375100=733.75. Now Ria has to pay ₹733.75 as the total fare.

The correct option is D
₹733.75

As the cab charges 2.5 times the normal fare, the original fare gets multiplied by the extra charges.

So, $2.5 \times 293.50 = \frac{25}{10} \times \frac{2935}{10} = \frac{73375}{100} = 733.75$ .

Now Ria has to pay ₹733.75 as the total fare.