Rice is mixed in the ratio 2: 3 and sold at Rs. 22 per kg, resulting in a profit of 10%. If the cost of the smaller quantity be Rs. 14 per kg, then the cost per kg of the larger quantity is :

Rs. 24

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RS. 23

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RS. 25

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RS. 28

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Solution

The correct option is A Rs. 24
Cost price of mixture per Kg= $\frac{22 \times 100}{110} = 20 R s .$
Let cost of larger quantity per Kg=x
then $\Rightarrow \frac{x - 20}{20 - 14} = \frac{2}{3}$
$\Rightarrow 3 x - 60 = 40 - 28$
$\Rightarrow 3 x = 72$
$\Rightarrow x = 24$

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The cost of type 1 rice is Rs. 10 per kg and type 2 rice is Rs. 20 per kg. If both type 1 and type 2 are mixed in the ratio of 2:3, then the price per kg of the mixed variety of rice is:

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Rice is mixed in the ratio 2: 3 and sold at Rs. 22 per kg, resulting in a profit of 10%. If the cost of the smaller quantity be Rs. 14 per kg, then the cost per kg of the larger quantity is :

The correct option is A Rs. 24Cost price of mixture per Kg=22×100110=20Rs.Let cost of larger quantity per Kg=xthen⇒x−2020−14=23⇒3x−60=40−28⇒3x=72⇒x=24

The correct option is A Rs. 24
Cost price of mixture per Kg= $\frac{22 \times 100}{110} = 20 R s .$
Let cost of larger quantity per Kg=x
then $\Rightarrow \frac{x - 20}{20 - 14} = \frac{2}{3}$
$\Rightarrow 3 x - 60 = 40 - 28$
$\Rightarrow 3 x = 72$
$\Rightarrow x = 24$