Riemer Tiemann reaction introduces an aldehyde group, on to the aromatic ring of phenol, ortho to the hydroxyl group. This reaction involves electrophilic aromatic substitution. This is a general method for the synthesis of substituted salicylaldehydes as depicted below

The electrophile in this reaction is

CHCl

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$+ C H C l_{2}$

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$C C l_{2}$

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$∙ C C l_{3}$

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Solution

The correct option is C
$C C l_{2}$

The first step is that of the formation of dichlorocarbene via $α$ elimination:

The dichlorocarbene is electron deficient and the activated phenoxide is electron-rich:

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The correct option is C CCl2 The first step is that of the formation of dichlorocarbene via α elimination: The dichlorocarbene is electron deficient and the activated phenoxide is electron-rich:

The correct option is C
$C C l_{2}$

The first step is that of the formation of dichlorocarbene via $α$ elimination:

The dichlorocarbene is electron deficient and the activated phenoxide is electron-rich: