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Question

Rima was given two test tubes labelled A and B. When she dipped an iron nail in both the test tubes, she observed that the colour of the solution changed as shown in the image given below. Identify the solutions in test tubes A and B.

A
Solution in test tube A is FeSO4 and that in test tube B is CuSO4
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B
Solution in test tube A is ZnSO4 and that in test tube B is CuSO4
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C
Solution in test tube A is CuSO4 and that in test tube B is ZnSO4
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D
Solution in test tube A is CuSO4 and that in test tube B is FeSO4
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Solution

The correct option is D Solution in test tube A is CuSO4 and that in test tube B is FeSO4
The blue coloured solution in test tube A is CuSO4 while the green coloured solution in test tube B is FeSO4. When an iron nail is dipped in test tube A, Fe displaces Cu from CuSO4 solution as Fe is more reactive than Cu. This causes the solution to turn green. The reaction occurs as follows:
Fe(s) + CuSO4(aq) FeSO4(aq) + Cu(s)

However, when an iron nail is dipped in test tube B containing FeSO4 solution, the colour of the solution remains the same. This is because, Fe of the nail cannot displace Fe of FeSO4 solution.

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