Ring structure of glucose is due to formation of hemiacetal and ring formation between -

C_{1} a n d C_{5}

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C_{1} a n d C_{4}

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C_{1} a n d C_{3}

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C_{2} a n d C_{4}

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Solution

The correct option is A $C_{1} a n d C_{5}$
Conceptual

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Furanose ring structure of fructose is due to hemiacetal formation between

N O_{3}

N O_{3}^{-}

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