Question

Ritu ate$\frac{3}{5}$ part of an apple and the remaining apple was eaten by her brother Somu. How many parts of the apple did Somu eat? Who had the larger share? By how much?

Answer 1

Part of the apple eaten by Ritu is = $\frac{3}{5}$

Part of apple eaten by Somu is = $1$– Part of the apple eaten by Ritu

$=1–\frac{3}{5}$

Converting the given fraction into an equivalent fraction having$10$ as the denominator.

$$\begin{gathered} =\left[\right(\frac{1}{1})\times (\frac{5}{5}\left)\right]–\left[\right(\frac{3}{5})\times (\frac{1}{1}\left)\right] \\ =\left(\frac{5}{5}\right)–\left(\frac{3}{5}\right) \\ =\frac{(5–3)}{5} \\ =\frac{2}{5} \end{gathered}$$

∴ Part of the apple eaten by Somu is$\frac{2}{5}$

So, $\left(\frac{3}{5}\right)>\left(\frac{2}{5}\right)$

Hence, Ritu ate a larger size of an apple.

The difference between the$32$ shares$=\left(\frac{3}{5}\right)–\left(\frac{2}{5}\right)$

$$\begin{gathered} =\frac{(3–2)}{5} \\ \mathbf{=}\frac{\mathbf{}\mathbf{1}}{\mathbf{5}} \end{gathered}$$

Ritu’s share is larger than the share of Somu by ($\frac{\mathbf{1}}{\mathbf{5}}$)