Question

Ritu is $5$ years younger than her brother Rohit. Their father is $25$ years older than Ritu. Four years ago, the fathers age was twice the sum of the ages of Rohit and Ritu then, Find present age of each.

• A. Ritu $=12$ year , Rohit $=18$ years and father $=40$ years
• B. Ritu $=9$ year , Rohit $=14$ years and father $=34$ years
• C. Ritu $=10$ year , Rohit $=19$ years and father $=44$ years
• D. Ritu $=11$ year , Rohit $=16$ years and father $=37$ years

Answer 1

The correct option is B Ritu $=9$ year , Rohit $=14$ years and father $=34$ years

Let Rohit's age be $x$ years.
Since, Ritu is $5$ years younger than her brother Rohit, her age $=x-5$
Given, father is $25$ years older than Ritu => Father's age $=x-5+25=x+20$
Four years ago, Rohit's age $=x-4$, Ritu's age $=x-9$, Father's age $=x+16$
Given, four years ago, the fathers age was twice the sum of the ages of Rohit and Ritu
$=>x+16=2(x-4+x-9)$
$=>x+16=4x-26$
$=>3x=42$
$x=14$
Hence, Rohit's age $=14$ years
Ritu's age $=x-5=9$ years
Father's age $=x+20=34$ years