The correct option is C π2
Let sin−1(a)=yBefore assuming such things we have to check certain conditions. Given that −1≤a≤1Thus we can assume sin−1(a)=y,as the domain of sin−1(x) can be [−1,1].So,sin−1(a)=y ;−π2≤y≤π2or, a=sin(y)Also,a=cos(π2−y)π2−y=cos−1(a) (We could write this equation because a ϵ[−1,1]−yϵ[0,π])π2=cos−1(a)+y =sin−1(a)+cos−1(a)=π2 (Since, sin−1(a)=y)