In the figure, given alongside, PB and QA are perpendiculars to the line segment AB. If PO=3cm,QO=4.5cm and area of △ POB=60 cm2, find the area of △ QOA.
135 cm2
in △POB and △QOA1. ∠POB=∠QAO [Each900]2. ∠POB=∠QOA [Vetically opposite angles]⇒△POB∼△QOA [ByA.A]Ar.(△POB)Ar.(△POB)=PO2QO2[Ratio between the areas of twosimilar triangles is equal to the ratio between the squares of the corresponding sides]⇒60Ar.(△QOA)=324.52⇒Ar.(△QOA)=69×20.259 cm2=135cm2