In the given figure, DE∥BC.Then, △ ADE is not similar to △ ABC
True
False
(i)DE∥BC⇒∠ADE=∠ABC [Corresponding angles]And,∠AED=∠ACB [Corresponding angles]∴△AED∼△ABC
Hence the statement is incorrect.
In the figure, AD = AE and AD2=BD×EC. Then triangles ABD and CAE are not similar triangles.
In the given figure, AD = DC, AB = CB and if ∠A and ∠C are 90∘ respectively, then, the figure is a parallelogram.
In the figure given above, AC is the diameter. AB, BC, AD, DC are chords of the circle.
AD = BC = 3 cm.
Then, ΔABC≅ΔADC