$s i n^{2} 1 + s i n^{2} 89 + c o s^{2} 7 + c o s^{2} 83 = ?$

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Solution

The correct option is D
2

$\begin{matrix} U s i n g s i n^{2} A + c o s^{2} A = 1 a n d s i n (90 - θ) = c o s θ w e g e t = s i n^{2} 1 + s i n^{2} (90 - 1) + c o s^{2} 7 + c o s^{2} (90 - 7) = s i n^{2} 1 + c o s^{2} 1 + c o s^{2} 7 + s i n^{2} 7 = 1 + 1 = 2 . \end{matrix}$

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Similar questions

The value of ${sin}^{2} 1^{\circ} + {sin}^{2} 2^{\circ} + {sin}^{2} 2^{\circ} + . . . + {sin}^{2} 89^{\circ} + {sin}^{2} 90^{\circ}$

Q. Prove that

\frac{cos 27 + sin 27}{cos 27 - sin 27} = tan 72

Find the sum of:
$s i n^{2} 1^{\circ} + s i n^{2} 2^{\circ} + s i n^{2} 3^{\circ} + s i n^{2} 4^{\circ} + . . . . . . . . . . s i n^{2} 89^{\circ} + s i n^{2} 90^{\circ}$

Q. The value of

sin 27^{\circ} - cos 27^{\circ}

is equal to

Q. Evaluate the following :

\frac{s i n 21}{c o s 69}

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sin21+sin289+cos27+cos283=?

The correct option is D 2 Usingsin2A+cos2A=1 and sin(90−θ)=cosθ we get=sin21+sin2(90−1)+cos27+cos2(90−7)=sin21+cos21+cos27+sin27=1+1=2.

$s i n^{2} 1 + s i n^{2} 89 + c o s^{2} 7 + c o s^{2} 83 = ?$

The correct option is D
2

$\begin{matrix} U s i n g s i n^{2} A + c o s^{2} A = 1 a n d s i n (90 - θ) = c o s θ w e g e t = s i n^{2} 1 + s i n^{2} (90 - 1) + c o s^{2} 7 + c o s^{2} (90 - 7) = s i n^{2} 1 + c o s^{2} 1 + c o s^{2} 7 + s i n^{2} 7 = 1 + 1 = 2 . \end{matrix}$