When CH 2- CH - COOH is reduced by LiAIH 4- the compound obtained is -A- CH 3 CH 2 COOHB- CH 2- CHCH 2 OHC- CH 3 CH 2 CHOD- CH 3 CH 2 CH 2 OH

The correct option is B CH2=CHCH2OH LiAIH_4 reduces COOH to CH_2OH but does not influence C=C. ...

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Synthesis of Ethers

When CH 2= CH...

Question

$W h e n C H_{2} = C H - C O O H i s r e d u c e d b y L i A I H_{4}, t h e c o m p o u n d o b t a i n e d i s :$

CH₃CH₂COOH

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CH₃CH₂CH₂OH

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CH₂=CHCH₂OH

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CH₃CH₂CHO

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Solution

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C H_{2} = C H - C O O H

L i A l H_{4}

(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

(C) C | C O O H H_{2} - C H_{2} - C H_{2} - - C H - C H_{3}

H O O C - C H_{2} - C | H C O O H - C H_{2} - C O O H

C H_{3} - C H_{2} - C H | C O O H - C H_{2} - C l | C H - C H_{2} - C H_{3}

H O O C - C H - 2 - H O O C - C H_{2} | C H - C H_{2} - C H_{2} - C O O H

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