Question

RMS current of the given saw tooth A.C current is

• A. $\frac{2}{\sqrt{3}}A$
• B. $0A$
• C. $\sqrt{\frac{2}{3}}A$
• D. $1A$

Answer 1

The correct option is A $\frac{2}{\sqrt{3}}A$

$i=(2t-2)Averageof{i}^2,<i^2>=\frac{{\int }_0^2(2t-2{)}^{2}dt}{{\int }_0^{2}dt}=\frac{[\frac{(2t-2{)}^3}{3\times 2}{]}_0^2}{2}=\frac{4}{3}$
where, $I_{rms}=\sqrt{2}\times I_{peak}$
So, $i_{irms}=\sqrt{<i^2>}=\frac{2}{\sqrt{3}}$ $A$