Roasted copper pyrite on smelting with sand produces:

F e S i O_{3}

as fusible slag and

C u_{2} S

as mattee'

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C a S i O_{3}

as infusible slag and

C u_{2} O

as mattee'

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C a_{3} (P O_{4})_{2}

as fusible slag and

C u_{2} S

as mattee'

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F e_{3} (P O_{4})_{2}

as infusible slag and

C u_{2} S

as mattee'

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Solution

The correct option is A $F e S i O_{3}$ as fusible slag and $C u_{2} S$ as mattee'
Roasted copper pyrite on smelting with sand produces $F e S i O_{3}$ as fusible slag and $C u_{2} S$ as mattee.
$2 C u F e S_{2} + O_{2} \to C u_{2} S + 2 F e S + S O_{2}$
$2 F e S + 3 O_{2} \to 2 F e O + 2 S O_{2}$
$F e O + S i O_{2} \to F e S i O_{3} \to F e S i O_{3} (s l a g)$

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Roasted copper pyrite on smelting with sand produces:

The correct option is A FeSiO3 as fusible slag and Cu2S as mattee'Roasted copper pyrite on smelting with sand produces FeSiO3 as fusible slag and Cu2S as mattee. 2CuFeS2+O2→Cu2S+2FeS+SO22FeS+3O2→2FeO+2SO2FeO+SiO2→FeSiO3→FeSiO3(slag)