ROCK is a rectangle with sides 8 cm and 6 cm. BAND is a rhombus obtained by joining the mid-points of the sides of the rectangle. Find the area of BAND in sq cm.

24

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Solution

The correct option is A 24

Construction: Join AD and BN to get the diagonals of the rhombus BAND.

Given: OC = 8 cm and OR = 6 cm

$O C = A D = d_{1} = 8 c m O R = N B = d_{2} = 6 c m$

$Area of the rhombus BAND = \frac{1}{2} \times d_{1} \times d_{2} = \frac{1}{2} \times 8 \times 6 = 24 c m^{2}$

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ROCK is a rectangle with sides 8cm and 6cm. BAND is a rhombus obtained by joining the mid-points of the sides of the rectangle. Find the area of BAND.

The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm, is_________.

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(a) a rhombus of area 24 cm²

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(c) a square of area 26 cm²

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8 c m

and

6 c m

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ROCK is a rectangle with sides 8 cm and 6 cm. BAND is a rhombus obtained by joining the mid-points of the sides of the rectangle. Find the area of BAND in sq cm. 24

The correct option is A 24 Construction: Join AD and BN to get the diagonals of the rhombus BAND. Given: OC = 8 cm and OR = 6 cm OC=AD=d1=8 cmOR=NB=d2=6 cm Area of the rhombus BAND=12×d1×d2=12×8×6=24 cm2

ROCK is a rectangle with sides 8 cm and 6 cm. BAND is a rhombus obtained by joining the mid-points of the sides of the rectangle. Find the area of BAND in sq cm.

24

The correct option is A 24

Construction: Join AD and BN to get the diagonals of the rhombus BAND.

Given: OC = 8 cm and OR = 6 cm

$O C = A D = d_{1} = 8 c m O R = N B = d_{2} = 6 c m$

$Area of the rhombus BAND = \frac{1}{2} \times d_{1} \times d_{2} = \frac{1}{2} \times 8 \times 6 = 24 c m^{2}$