Rohan is pulling a trolley of mass 10 kg with a force of 25 N. The friction that can be applied by the floor on the trolley is 50 N. Calculate the push force applied by Rahul if the trolley is moving towards left with an acceleration of 0.5m/s2.
According to the second law of motion,
Fnet = m.a
Fnet = 100.5 = 5 N
Fnet = Sum of all the forces acting on the trolly
Fnet = FRohan + Ffriction + FRahul
5 = 25 + (-50) + FRahul
FRahul = 30 N