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Question

Rohan is pulling a trolley of mass 10 kg with a force of 25 N. The friction that can be applied by the floor on the trolley is 50 N. Calculate the push force applied by Rahul if the trolley is moving towards left with an acceleration of 0.5m/s2.


A
35 N
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B
30 N
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C
40 N
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D
25 N
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Solution

The correct option is B 30 N

According to the second law of motion,
Fnet = m.a

Fnet = 100.5 = 5 N

Fnet = Sum of all the forces acting on the trolly

Fnet = FRohan + Ffriction + FRahul

5 = 25 + (-50) + FRahul

FRahul = 30 N

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