Rohan is pulling a trolley with a force of 25N. The maximum friction that can be applied by the floor on the trolley is 60N. What should be the minimum force that Rahul should apply to move the trolley?
A
25N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
35N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
85N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
60N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B35N Given:
Let’s assume that all the forces acting along the left hand side are negative and the forces along the right hand side are positive.
Force applied by Rohan along the left hand side = +25N
Friction force along the right hand side = −60N
Rahul to help out Rohan, he should apply force along the left hand side. Let his force = +XN
The net force of the complete system must be zero. Hence, the minimum force that Rohan should apply can be found out by equating the sum of all the forces in the system to zero.
+25 + (-60) + X = 0
X = 35 N