Rohit and Rahul both are pulling a block with 20 N and 30 N force respectively in same direction and net displacement in the direction of applied force is 50 m. The net work done is

2000 J

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2500 J

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1000 J

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1500 J

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Solution

The correct option is B 2500 J
Since the direction of the forces being applied is the same, the forces get added to each other.

So, the net force applied = $20 N + 30 N = 50 N$

Work $=$ Force $\times$ Displacement
$= (20 + 30) \times 50$
$= 2500 J$

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Rohit and Rahul both are pulling a block with 20 N and 30 N force respectively in same direction and net displacement in the direction of applied force is 50 m. The net work done is

The correct option is B 2500 JSince the direction of the forces being applied is the same, the forces get added to each other. So, the net force applied = 20 N+30 N=50 N Work = Force×Displacement =(20+30)×50 =2500J

The correct option is B 2500 J
Since the direction of the forces being applied is the same, the forces get added to each other.

So, the net force applied = $20 N + 30 N = 50 N$

Work $=$ Force $\times$ Displacement
$= (20 + 30) \times 50$
$= 2500 J$