Question

Rohit and Vinit individually took $\frac{1^{th}}{4}$and $\frac{1^{th}}{6}$ of an hour, respectively to reach their friend's house. Who took more time?

Answer 1

Since, the Denominator are not same.

To make the denominator same

Consider the denominator of given fraction as $4,6$

The LCM of $4,6$ is $12$

The fraction becomes

$\frac{1}{4}\times 12=3$

Hence, $\frac{1}{4}\times \frac{3}{3}=\frac{3}{12}$

Also $\frac{1}{6}\times 12=2$

Hence, $\frac{1}{6}\times \frac{2}{2}=\frac{2}{12}$

Now, Consider $\frac{3}{12}$ and $\frac{2}{12}$

$$\begin{gathered} \frac{3}{12}?\frac{2}{12} \\ 3\times 12?2\times 12 \\ 36?24 \\ 36>24 \end{gathered}$$

Since, $36$ is greater than $24$

Hence, $\frac{3}{12}>\frac{2}{12}$

Or, $\frac{1}{4}>\frac{1}{6}$

Hence, Rohit took more time to reach his friend's house.