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Standard VI

Mathematics

Cardinality

Rohit has mar...

Question

Rohit has marks of 92, 85, and 78 in three mathematics tests. In order to have an average of exactly 87 for the four math tests, he should obtain:

92 marks

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91 marks

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95 marks

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93 marks

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Solution

The correct option is D 93 marks
$\frac{x + 92 + 85 + 78}{4} = 87 \Rightarrow x + 92 + 85 + 78 = 87 \times 4 \Rightarrow x = 348 - 92 - 85 - 78 \Rightarrow x = 93$

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Rohit has marks of 92, 85, and 78 in three mathematics tests. In order to have an average of exactly 87 for the four math tests, he should obtain:

The correct option is D 93 marksx+92+85+784=87⇒x+92+85+78=87×4⇒x=348−92−85−78⇒x=93

The correct option is D 93 marks
$\frac{x + 92 + 85 + 78}{4} = 87 \Rightarrow x + 92 + 85 + 78 = 87 \times 4 \Rightarrow x = 348 - 92 - 85 - 78 \Rightarrow x = 93$