wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Rolle's theorem is applicable in the interval [2,2] for the function

A
f(x)=x3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
f(x)=4x4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
f(x)=2x3+3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
f(x)=π|x|
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B f(x)=4x4
If we take f(x)=4x4, then
(i) f(x) is continuous in (2,2)
(ii) f(x) is differentiable in (2,2)
(iii) f(2)=f(2)
So, f(x)=4x4 satisfies all the conditions of Rolle's theorem, therefore a point c such that f(c)=0
16c3=0c=0ϵ(2,2)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems for Differentiability
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon