Root mean square speed of the molecules of ideal gas is $v$ . If pressure is increased two times at constant temperature, the $r m s$ speed will become:

2 v

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\frac{v}{2}

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4 v

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v

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Solution

The correct option is D $v$
$v_{r m s} = \sqrt{\frac{3 R T}{M}}$
As T is constant
Though pressure is increased $v_{r m s}$ remains unchanged

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