Root mean square velocity of a gas molecule is proportional to

m^1/2

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m⁰

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m^-1/2

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Solution

The correct option is C
m^-1/2

$V_{r m s} = \sqrt{\frac{3 K T}{M o l e c u l a r w e i g h t}} i . e . v_{r m s} α \frac{1}{\sqrt{m}} α (m)^{\frac{1}{2}}$

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Similar questions

The root mean square velocity of a gas molecule of mass m at a given temperature is proportional to

s^{- 1}

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