Root of quadratic equation $2 p^{2} + 5 p - 3 = 0$ is

- 3

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\frac{- 1}{2}

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1

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None of these

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Solution

The correct option is D $- 3$
Given quadratic equation is $2 p^{2} + 5 p - 3 = 0$ .
It can be written as:
$2 p^{2} + 6 p - p - 3 = 0$
$\Rightarrow 2 p (p + 3) - 1 (p + 3) = 0$

$\Rightarrow (2 p - 1) (p + 3) = 0$

So, $(2 p - 1) = 0$ or $(p + 3) = 0$
$∴ p = \frac{1}{2}$ or $p = - 3$

Given options only has $- 3$ and not $\frac{1}{2}$ .
Hence, option A is correct.

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If $x^{2}$ +px + q = 0 is the quadratic equation whose roots are a – 2 and b – 2 where a and b are the roots of $x^{2}$ - 3x + 1 =0, then

p

(p^{2} - 5 p + 3) x^{2} + (3 p - 1) x + 2 = 0

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