Question

Roots of quadratic equation $2n^2+5n+2=0$ are

• A. $n=-8,\frac{-1}{2}$
• B. $n=-2,\frac{-1}{5}$
• C. $n=-2,\frac{1}{2}$
• D. $n=-2,\frac{-1}{2}$

Answer 1

Answer: (D)

$n=-2,\frac{-1}{2}$

Given equatioon is,

$2n^2+5n+2=0$
$2n^2+4n+n+2=0$
$2n(n+2)+1(n+2)=0$
$(2n+1)(n+2)=0$

$\therefore n=-2,\frac{-1}{2}$

$\therefore$ roots of the equation are $-2,\frac{-1}{2}$