Roots of quadratic equation $7 p^{2} - 5 p - 2 = 0$ are

p = 3, \frac{- 2}{7}

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p = 2, \frac{- 2}{7}

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p = 1, \frac{- 2}{7}

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p = 1, \frac{2}{7}

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Solution

The correct option is B $p = 1, \frac{- 2}{7}$
Given equation is,
$7 p^{2} - 5 p - 2 = 0$
$7 p^{2} - 7 p + 2 p - 2 = 0$
$7 p (p - 1) + 2 (p - 1) = 0$
$(7 p + 2) (p - 1) = 0$
$∴ p = \frac{- 2}{7}, 1$
$∴$ roots of the given equation are $\frac{- 2}{7}, 1$

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