Question

Roshan's mother gave him ₹ $(6x^{2}y+6x)$ and his father gave him ₹ $6(x^{2}y+2x+2)$ out of this total money he spent ₹ $3(x^{2}y+x+1)$ on his birthday party. If x = 1 and y = 2, then find the total amount left with him?

• A. ₹ 27
• B. ₹33
• C. ₹40
• D. ₹42

Answer 1

The correct option is D ₹42

The amount given by Roshan's mother
$=₹(6x^{2}y+6x)$
The amount given by Roshan's father
$=₹6(x^{2}y+2x+2)$.
Total amount
$=₹(6x^{2}y+6x)+₹\left(6\right(x^{2}y+2x+2)$
$=₹(12x^{2}y+18x+12)$
Total amount Roshan spent
$=₹(3x^{2}y+3x+3)$
Amount of money left
$=₹(12x^{2}y+18x+12)-₹(3x^{2}y+3x+3)$
$=₹(9x^{2}y+15x+9)$.
Substituting the value of x = 1 and y = 2 in the above expression,
Amount of money left with Roshan $=9\left(1{)}^2\right(2)+15(1)+9$
= 18 + 15 + 9 = ​​​​​​​ ₹ 42.
Hence, the amount left with Roshan is ​​​​​​​= ₹ 42.