Question

Round the following decimal numbers upto 3 place of decimal
(a) $24.4003$
(b) $1251.2345$
(c) $61.00203$

Answer 1

(a) $24.4003$
Rounding $24.4003$ upto 3 places of decimal means rounding to the nearest thousandths place. Underlining the digit in the thousandths place of $24.4003$ gives $24.40\underset{–}{0}3.\ln 24.40\underset{–}{0}3$ the digit next to the thousandths value is 3 which is less than 5.
$\therefore$ The underlined digit remains the same. So the rounded value of $24.4003$ upto 3 places of decimal is $24.400$.
(b) $1251.2345$
Rounding $1251.2345$ upto 3 places of decimal means rounding to the nearest thousandths place. Underlining the digit in the thousandths place of $1251.2345$ gives $1251.2345$, the digit next to the thousandths place value is 5 and so we add 1 to the underlined digit. So the rounded value of $1251.2345$ upto 3 places of decimal is $1251.235$.
(c) $61.00203$
Rounding $61.00203$ upto 3 places of decimal means rounding to the nearest thousandths place. Underlining the digit in the thousandth place of $61.00203$ gives 61.00203. In 61.00203, the digit next to the thousandths place value is 0 , which is less than 5 .

Hence the underlined digit remains the same. So the rounded value of $61.00203$ upto 3 places of decimal is $61.002$.