$R s 7000$ is borrowed at $3.5 %$ rate of interest p.a. $2 y e a r s$ .Find the amount to be paid at the end of second year.

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Solution

Given, $P = R s 7000, R = 3.5 %, T = 2 y e a r s$ .
We know that,
$S . I . = \frac{P \times R \times T}{100} = \frac{7000 \times 3.5 \times 2}{100} = 70 \times 7 = 490 R s$
Now ,
$A m o u n t = P + S . I . = 7000 + 490 = 7490 R s$
Therefore, $R s 7490$ amount is to be paid at the end of second year.

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Rs7000 is borrowed at 3.5%rate of interest p.a. 2years.Find the amount to be paid at the end of second year.

Given, P=Rs7000,R=3.5%,T=2years.We know that, S.I.=P×R×T100=7000×3.5×2100=70×7=490RsNow , Amount=P+S.I.=7000+490=7490RsTherefore, Rs7490amount is to be paid at the end of second year.

$R s 7000$ is borrowed at $3.5 %$ rate of interest p.a. $2 y e a r s$ .Find the amount to be paid at the end of second year.