Rust contains $F e_{2} O_{3} . H_{2} O$ . Rust spots can be removed by:

N a_{2} S_{2} O_{3}

(hypo)

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S O_{2}

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H_{2} C_{2} O_{4}

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K M n O_{4}

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Solution

The correct option is B $H_{2} C_{2} O_{4}$
Rust contains $F e_{2} L_{3} . H_{2} O$ . Iron is present in +3 oxidation state. It reacts with oxalic acid to form soluble complex.
Thus, rust spots can be removed by the reaction with oxalic acid.

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Similar questions

(F e_{2} O_{3})

F e_{2} C O_{3} (s) + 6 H_{2} C_{2} O_{4} \to 2 F e_{2} {(C_{2} O_{4})_{3}}^{3 -} + 3 H_{2} O + H^{+}

5.00 \times 10^{2}

1

H C l

F e_{2} O_{3}

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