Rusting of iron requires the presence of:

Air and water

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C O_{2}

and water

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O_{2}

and

H_{2}

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O_{2}

and

N_{2}

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Solution

The correct option is A Air and water
Rusting of iron is the surface oxidation of metallic iron in the presence of atmospheric moisture (water) and oxygen (air).
Reactions involved:
$O_{2} + 2 H_{2} O \to 4 O H^{-}$
$F e^{2 +} (a q) + 2 O H^{-} (a q) \to F e (O H)_{2} (s)$
$4 F e (O H)_{2} (s) + O_{2} (g) + 2 H_{2} O (l) \to F e (O H)_{3} (s)$
Option A is correct

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