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Question

S is a point on the side QR of triangle PQR such that PS is the bisector of angle QPR then:


A

QS=SR

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B

QP>QS

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C

QS>QP

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D

SR>RP

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Solution

The correct option is B

QP>QS


According to the given condition, QPS=RPS

By external angle theorem,

PSQ=RPS+PRSPSQ=QPS+PRSPSQ>QPS

In a triangle, the side opposite to the greater angle is greater. Therefore,

QP>QS

Hence, option B is correct.


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