$S - O$ bond length is maximum in:

S O B r_{2}

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S O C l_{2}

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S O F_{2}

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S O (C H_{3})_{2}

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Solution

The correct option is B $S O B r_{2}$
Larger the bond angle, shorter the bond length; greater the size of halogen, greater will be the $S - X$ angle and less will be $S - O$ bond angle. So, order of $S - O$ bond angle is $S O B r_{2} < S O C l_{2} < S O F - 2$ ; since $B r > C l > F$ . Hence, bond length will be maximum in $S O B r_{2}$ .

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