S : The red colour shown by ${[F e (S C N)]}^{2 +} (a q)$ in a reversible reaction between ${F e}^{3 +}$ and ${S C N}^{-}$ .
${F e}^{3 +} (a q) + {S C N}^{-} (a q) ⇌ F e {(S C N)}^{2 +} (a q)$ deepens if few more drops of $K S C N$ are added in equilibrium mixture.
E : Addition of $K S C N$ favours backward reaction.

S is correct but E is wrong

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S is wrong but E is correct

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Both S and E are correct and E is correct explanation of S

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Both S and E are correct but E is not correct explanation of S

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Solution

The correct option is A S is correct but E is wrong
Option (A) is correct.
$E$ : Addition of $K S C N$ favours forward reaction.When $K S C N (a q)$ was added, by Le Chatelier's principle, the position of equilibrium would shift to the right so as to remove some of the extra $S C N^{-}$ . More $F e {(S C N)}^{2 +} (a q)$ produced and the solution became darker red.

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S : The red colour shown by [Fe(SCN)]2+(aq) in a reversible reaction between Fe3+ and SCN−. Fe3+(aq)+SCN−(aq)⇌Fe(SCN)2+(aq) deepens if few more drops of KSCN are added in equilibrium mixture.E : Addition of KSCN favours backward reaction.