S1- AM - AP -2- BN - BP -2S2- OO - AM - BNWhich of the above statements are true-A- Only S1 is true-B- Only S2 is true-C- Both statements are true-D- S 1 is true - S2 is false-

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Perpendicular from the Center to a Chord Bisects the Chord

S1: AM = AP /...

Question

S1: AM = $\frac{A P}{2}$ , BN= $\frac{B P}{2}$

S2: OO' = AM + BN

Which of the above statements are true ?

Only S1 is true.

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Only S2 is true.

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Both statements are true.

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S1 is true & S2 is false.

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Solution

The correct option is C
Both statements are true.

S1 is true as the perpendicular from the Centre of the circle bisects the chord into two parts.

Therefore AM = $\frac{A P}{2}$ , BN= $\frac{B P}{2}$

& OO’ = MN

= PM + PN

= AM + BN (as PM = AM & PN = BN)

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S1: AM = AP2, BN= BP2 S2: OO' = AM + BN Which of the above statements are true ?

The correct option is C Both statements are true. S1 is true as the perpendicular from the Centre of the circle bisects the chord into two parts. Therefore AM = AP2, BN= BP2 & OO’ = MN = PM + PN = AM + BN (as PM = AM & PN = BN)

S1: AM = $\frac{A P}{2}$ , BN= $\frac{B P}{2}$

S2: OO' = AM + BN

Which of the above statements are true ?

The correct option is C
Both statements are true.

S1 is true as the perpendicular from the Centre of the circle bisects the chord into two parts.

Therefore AM = $\frac{A P}{2}$ , BN= $\frac{B P}{2}$

& OO’ = MN

= PM + PN

= AM + BN (as PM = AM & PN = BN)