Saanvi wrote IUPAC names for a few compounds, as asked by her science teacher. The teacher told her that one of the compounds was not named correctly. Identify the one with the wrong name.

{CH}_{3} - {CH}_{2} - C = O - CH

: Propanal

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{CH}_{3} - {CH}_{2} - C = O - {CH}_{3}

: Butanone

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{CH}_{3} - {CH}_{2} - C = O - OH

: Ethanoic Acid

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{CH}_{3} - {CH}_{2} - {CH}_{2} - {CH}_{2} - OH

: Butanol

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Solution

The correct option is C ${CH}_{3} - {CH}_{2} - C = O - OH$ : Ethanoic Acid
The third compound have three carbon atoms so the root word is ‘prop’.It has functional group –COOH. So the third compound is propanoic acid and not ethanoic acid.

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Saanvi wrote IUPAC names for a few compounds, as asked by her science teacher. The teacher told her that one of the compounds was not named correctly. Identify the one with the wrong name.

The correct option is C CH3−CH2−C=O−OH: Ethanoic AcidThe third compound have three carbon atoms so the root word is ‘prop’.It has functional group –COOH. So the third compound is propanoic acid and not ethanoic acid.

The correct option is C ${CH}_{3} - {CH}_{2} - C = O - OH$ : Ethanoic Acid
The third compound have three carbon atoms so the root word is ‘prop’.It has functional group –COOH. So the third compound is propanoic acid and not ethanoic acid.