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Question

Sachin and Rahul attempted to solve a quadratic equation. Sachin made a mistake in writing down the constant term and ended up in roots (4, 3). Rahul made a mistake in writing down coefficient of x to get roots (3, 2). The correct roots of equation are:

A
6, 1
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B
4, 3
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C
-6, -1
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D
-4, -3
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Solution

The correct option is A 6, 1
Let ax2+bx+c=0 be the correct equation.
Sachin's equation: ax2+bx+c=0 has roots (4,3)
Rahul's equation: ax2+bx+c=0 has roots (3,2)
Therefore, ba=7 and ca=6 Or, b=7a and c=6a
So, the correct equation is : ax27ax+6a=0 Or, x27x+6=0 Its roots are 6,1.

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