Question

Sachin had $\frac{2}{6}$ of a cake. He ate $\frac{1}{3}$ of it. What part of the cake did he eat?

• A. $\frac{1}{9}$
• B. $\frac{9}{2}$
• C. $\frac{2}{9}$
• D. $\frac{1}{6}$

Answer 1

The correct option is A $\frac{1}{9}$

$\frac{2}{6}\times \frac{1}{3}=\frac{1}{3}\times \frac{1}{3}=\frac{1}{9}$

Hence, Sachin ate $\frac{1}{9}$th part of the cake.

Option C is the correct answer.