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Question

# Sahil rides his bicycle at the speed of 15km/h and reaches school late by 2 minutes. On increasing the speed by 5km/ h , he reaches 8 minutes early. Find the distance between the school and his house.

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Solution

## Let the distance between his school and home be x km. Then, the time taken by him to reach the school when his speed is 15 km/h =x15hours=60×x15minutes=4xminutes (Times=distancespeedand1hour=60minutes) The time taken by him to reach the school when his speed increases by 5 km/h i.e. at speed of 20 km/h =x20hours=60×x20minutes=3xminutes According to the question, at speed of 15 km/h Sahil reaches school late by 2 minutes; and at speed of 20 km/h he reaches school 8 minutes early. So, there is a difference of 10 minutes between the times taken at speed of 15 km/h and at speed of 20 km/h. Therefore we can write 4x−3x=10 ⇒x=10 Hence the distance between his home and school is 10 km.

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